AP Physics 1 Question 286: Answer and Explanation
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4. A car of mass 1000 kg is traveling at a speed of 5 m/s. The driver applies the breaks, generating a constant friction force, and skids for a distance of 20 m before coming to a complete stop. Given this information, what is the coefficient of friction between the car's tires and the ground?
- A. 0.25
- B. 0.2
- C. 0.125
- D. 0.0625
Correct Answer: D
First, you know Ff = μFN = µ(mg). Second, you know that W = ΔKΕ = KEf - KE0 = -KE0 (since KEf = 0 in this case) = - mv02. Plugging in numbers, you get W = - (1000 kg)(5 m/s)2 = -12,500 J. You also know that W = Fdcosθ = [µ(mg)]dcosθ. Solving for μ, you get μ = W/[(mg)dcosθ]. Plugging in the numbers then gives μ = -12,500 J/[(1000 kg)(10 m/s2)(20 m)(cos180°)] = 0.0625.