AP Physics 1 Question 393: Answer and Explanation
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1. A 2000 kg truck traveling north at 40.0 m/s collides with a 1500 kg car traveling west at 20.0 m/s. If the two vehicles lock bumpers and stick together, what is the angle of the velocity after impact?
- A. 69.4° north of west
- B. 20.6° north of west
- C. 20.6° north of east
- D. 69.4° north of east
Correct Answer: A
As the collision is perfectly inelastic, the final momentum is the vector sum of the initial momentums of both vehicles. As only the truck is traveling in the north-south direction, the vertical momentum after impact is given by
py = mtruckvtruck = 2000 kg (40 m/s) = 80,000 kg·m/s north
As only the car is traveling in the north-south direction, the horizontal momentum after impact is given by
px = mcarvcar = 1500 kg (20 m/s) = 30,000 kg·m/s north
The angle of the velocity after impact can be expressed using tan(θ) , so θ = = 69.4° north of west.