AP Physics 1 Question 437: Answer and Explanation

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Question: 437

5. Question below refers to the following scenario:

A 2 kg ball with a velocity of -20 m/s collides with the wall and bounces back with a velocity of 10 m/s.

What is the impulse during the collision?

  • A. 10 N·s
  • B. 20 N·s
  • C. 30 N·s
  • D. 60 N·s

Correct Answer: D

Explanation:

D

The impulse is equal to the change in linear momentum, which can be calculated as follows:

J = Δp = mΔv = m(vf - vi) = 2 kg(10 m/s - (-20 m/s)) = 60 N·s